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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A gas hydrogen like atoms can absorb radiations of 68eV. Consequently, the atoms emit radiations of only three different wavelengths. All the wavelengths are equal or smaller than that of the absorbed photon. (a) Determine the initial state of the gas atoms. (b) Identify the gas atoms. (c) Find the minimum wavelength of the emitted radiation. (d) Find the ionization energy and the respective wavelength for the gas atoms.

A gas hydrogen like atoms can absorb radiations of 68eV. Consequently, the atoms emit radiations of only three different wavelengths. All the wavelengths are equal or smaller than that of the absorbed photon. (a) Determine the initial state of the gas atoms. (b) Identify the gas atoms. (c) Find the minimum wavelength of the emitted radiation. (d) Find the ionization energy and the respective wavelength for the gas atoms.

A gas hydrogen like atoms can absorb radiations of 68eV. Consequently A is ahead of B in phase by 66^@. If the observation be taken from point P Among the two interfering monochromatic sources A and B such that PB-PA=lambda//4. Then the phase difference between the waves from A and B reaching P is