A force of F = 2xi + 2j + 3z^2k N is acting on a particle. Find the work done by this force in displacing the body from (1, 2, 3 )m to (3, 6, 1)m. 1)m. 2 3 )m to (3 6 A force of F = 2xi + 2j + 3z^2k N is acting on a particle. Find the work done by this force in displacing the body from (1 October 3, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related