A force F=a+bx acts on a particle in the x-direction, where a and b are constants.

August 30, 2020
Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,

A single conservative force actin on a particle varies as F = ( -Ax + Bx^2)i N, where A and B are constants and x is in meters. (a) Calculate the potential-energy function U(x) associated

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A single conservative force acting on a particle varies as F = (-Ax + Bx^2)i N, where A and B are constants and x is in metres. (a) Calculate the potential energy function U(x) associated with this force,

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If a particle moves in a potential energy field U = U0 - ax + bx^2, where a and b are positive constants, obtain an expression for the force actin on it as a function of position. At what point does the force vanish?

Question Answers

A force F=a+bx acts on a particle in the x-direction, where a and b are constants.

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A single conservative force actin on a particle varies as F = ( -Ax + Bx^2)i N, where A and B are constants and x is in meters. (a) Calculate the potential-energy function U(x) associated

A single conservative force acting on a particle varies as F = (-Ax + Bx^2)i N, where A and B are constants and x is in metres. (a) Calculate the potential energy function U(x) associated with this force,

If a particle moves in a potential energy field U = U0 - ax + bx^2, where a and b are positive constants, obtain an expression for the force actin on it as a function of position. At what point does the force vanish?

Question Answers

A force F=a+bx acts on a particle in the x-direction, where a and b are constants.

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A single conservative force actin on a particle varies as F = ( -Ax + Bx^2)i N, where A and B are constants and x is in meters. (a) Calculate the potential-energy function U(x) associated

A single conservative force acting on a particle varies as F = (-Ax + Bx^2)i N, where A and B are constants and x is in metres. (a) Calculate the potential energy function U(x) associated with this force,

If a particle moves in a potential energy field U = U0 - ax + bx^2, where a and b are positive constants, obtain an expression for the force actin on it as a function of position. At what point does the force vanish?