A force F=6xhati+2yhatj displaces a body from r1=3hati+8hatj to r2=5hati-4hatj. Find the work done by the force. A force F=6xhati+2yhatj displaces a body from r1=3hati+8hatj to r2=5hati-4hatj. Find the work done by the force. August 30, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
