A force F=(2i^+j^+3k^) N acts on a particle of mass 1 kg for 2s. If initial velocity of particle is u=(2j^+i^m/s. Speed of particle at the end of 2s will be A force F=(2i^+j^+3k^) N acts on a particle of mass 1 kg for 2s. If initial velocity of particle is u=(2j^+i^m/s. Speed of particle at the end of 2s will be November 26, 2020 Category: Arihant Physics by D.C Pandey , Chapter 8 - COM, Momentum and Collision , Volume 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related