A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which displaces it from its origin to the point r = (2i ^− j ^)m. The work done on the particle in joules is: A force F = (5i ^+3 j ^+2 k ^)N is applied over a particle which displaces it from its origin to the point r = (2i ^− j ^)m. The work done on the particle in joules is: December 6, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related