Question Answers

Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 4 - Work, Energy and Power > A force acts on a 2 kg object so that its position is given as a function of time as x=3t^2+5. What is the work done by this force in first 5 seconds ?

A force acts on a 2 kg object so that its position is given as a function of time as x=3t^2+5. What is the work done by this force in first 5 seconds ?

A force acts on a 2 kg object so that its position is given as a function of time as x=3t^2+5. What is the work done by this force in first 5 seconds ?