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Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 13 - Fluid Mechanics > A drop of some liquid of volume 0.04 cm^3 is placed on the surface of a glass slide. Then another glass slide is placed on it in such a way that the liquid forms a thin layer of area 20 cm^2 between the surfaces of the two slides. To separate the slides a force of 16×10^5 dyne has to be applied normal to the surfaces. The surface tension of the liquid is (in dyne.cm^−1):

A drop of some liquid of volume 0.04 cm^3 is placed on the surface of a glass slide. Then another glass slide is placed on it in such a way that the liquid forms a thin layer of area 20 cm^2 between the surfaces of the two slides. To separate the slides a force of 16×10^5 dyne has to be applied normal to the surfaces. The surface tension of the liquid is (in dyne.cm^−1):

A rectangular film of liquid is extended from (4cm×2cm) to (5cm×4cm). If the work done is 3 x 10^{-4}J the value of the surface tension of the liquid is