A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x=0 and the positive plate is at x=3d. The slab is equidistant from the plates. The capacitor is given some charge. As x goes from 0 to 3d, then The electric field in region II as in figure shown is : December 3, 2020 Category: Arihant Physics by D.C Pandey , Chapter 2 - Electrostatic Potential and Capacitance , Volume 2 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related