A constant force f = 3i+2j+2k acts on a particle displacing it from a position r1 = -i + j-2k to a new position r2 = i – j +3k. Find the work done by the force A constant force f=3i+2j+2k acts on a paticle displacing it from a position r1 = -i + j-2k August 30, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related