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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A conduting wire ABC (as shown) is moving with a constant velocity along horizontal direction. The magnetic field is perpendicular to the wire and directed into the page. AB =BC. Find the range of angle (θ) made by rod AB with horizontal at A so that value of induced emf at A is greater than at C

A conduting wire ABC (as shown) is moving with a constant velocity along horizontal direction. The magnetic field is perpendicular to the wire and directed into the page. AB =BC. Find the range of angle (θ) made by rod AB with horizontal at A so that value of induced emf at A is greater than at C

0). If the rod moves with a velocity v = v0 find the emf induced between the ends of the rod. L The magnetic field inn a region is given by B = k B0/L y where L is a fixed length. A conducting rod of length L lies along the Y - axis between the origin and the point (0