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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A triangular wire frame (each side = 2 m) is placed in a region of time variant magnetic field dB/dt = ( root 3 )T/s. The magnetic field is perpendicular to the plane of the triangle and its centre coincides with the centre of triangle. The base of the triangle AB has a resistance 1(Ω) while the other two sides have resistance 2(Ω) each. The magnitude of potential difference between the points A and B will be

A triangular wire frame (each side = 2 m) is placed in a region of time variant magnetic field dB/dt = ( root 3 )T/s. The magnetic field is perpendicular to the plane of the triangle and its centre coincides with the centre of triangle. The base of the triangle AB has a resistance 1(Ω) while the other two sides have resistance 2(Ω) each. The magnitude of potential difference between the points A and B will be

the current in wire AB is ( ab is one of the diameters ) The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate alpha. Resistance per unit length of the loop is rho. Then