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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A conducting rod of length l slides at constant velocity v on two parallel conducting rails, placed in a uniform and constant magnetic field B perpendicular to the plane of the rails as shown in Fig.3.49. A resistance R is connected between the two ends of the rails. (a) Idenify the cause which produces change in magnetic flux. (b) Identify the direction of current in the loop. ( c) Determine the emf induced in the loop. (d) Compute the electric power dissipated in the resistor. (e) Calcualte the mechenical power required to pull the rod at a constant velocity.

A conducting rod of length l slides at constant velocity v on two parallel conducting rails, placed in a uniform and constant magnetic field B perpendicular to the plane of the rails as shown in Fig.3.49. A resistance R is connected between the two ends of the rails. (a) Idenify the cause which produces change in magnetic flux. (b) Identify the direction of current in the loop. ( c) Determine the emf induced in the loop. (d) Compute the electric power dissipated in the resistor. (e) Calcualte the mechenical power required to pull the rod at a constant velocity.

A conducting rod of length l slides at constant velocity v on two parallel conducting rails A square loop of side l having resistance R moves with constant velocity v Twelve wires of equal lengths are connected in the form of skelton cube which is moving with a velocity v in the direction of magnetic field B.find the emf in each arm of cube.