Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A conducting rod of length 1 is moving on a horizontal smooth surface. Magnetic field in the region is vertically downward and magnitude B0. If centre of mass (COM) of the rod is translating with velocity v0 and rod rotates about COM with angular velocity v0/l, then potential difference between points O and A will be

A conducting rod of length 1 is moving on a horizontal smooth surface. Magnetic field in the region is vertically downward and magnitude B0. If centre of mass (COM) of the rod is translating with velocity v0 and rod rotates about COM with angular velocity v0/l, then potential difference between points O and A will be

0). If the rod moves with a velocity v = v0 find the emf induced between the ends of the rod. L The magnetic field inn a region is given by B = k B0/L y where L is a fixed length. A conducting rod of length L lies along the Y - axis between the origin and the point (0