A conducting ring of mass 2 kg and radius 0.5 m is placed on a smooth plane. The ring carries a current of i=4A. A horizontal magnetic field B=10T is switched on at time t = 0 as shown in fig The initial angular acceleration of the ring will be An electron is accelerated from rest through a potential difference V. This electron experiences a force F in a uniform magnetic field. On increasing the potential difference to V' the force experienced by the electron in the same magnetic field becomes 2F. Then the ratio (V'/V) is equal to October 14, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related