A condenser having a capacity of 6 μF is charged to 100 V and is then joined to an uncharged condenser of 14μF and then removed. The ratio of the charges on 6 μF and 14 μF and the potential of 6μF will be Three capacitors each of capacity 4 muF are to be connected in such a way that the effective capacitance is 6 muF. This can be done by Three plates A September 18, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related