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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A circuit has a section Ab shown in fig. The emf of the source equals E = 10V, the capacitances are equal to C1=1.0μF and C2=2.0μF, and the potential difference φA−φB = 5.0V. Find the voltage across each capacitor.

A circuit has a section Ab shown in fig. The emf of the source equals E = 10V, the capacitances are equal to C1=1.0μF and C2=2.0μF, and the potential difference φA−φB = 5.0V. Find the voltage across each capacitor.

A circuit has a section Ab shown in fig. The emf of the source equals E = 10V and the potential difference φA−φB = 5.0V. Find the voltage across each capacitor. the capacitances are equal to C1=1.0μF and C2=2.0μF