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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A charged particle of radius 5×10^−7 m is located in a horizontal electric field of intensity 6.28 × 10^5 V/m. The surrounding medium has the coeffiecient of viscosity η = 1.6 × 10^5 Ns/m^2. The particle starts moving under the effect of electric field and finally attains a uniform horizontal speed of 0.02 m/s. Find the number of electrons on it. Assume gravity free space.

A charged particle of radius 5×10^−7 m is located in a horizontal electric field of intensity 6.28 × 10^5 V/m. The surrounding medium has the coeffiecient of viscosity η = 1.6 × 10^5 Ns/m^2. The particle starts moving under the effect of electric field and finally attains a uniform horizontal speed of 0.02 m/s. Find the number of electrons on it. Assume gravity free space.

l is length of silk thread. Two small metal spheres having equal charges and mass are suspended from some point on the ceiling of a damp room with silk threads of equal length. Let centre to center distance between sphere be x X