A charged particle of mass 5 mg and charge q = +2μC has velocity v = 2iˆ−3jˆ+4kˆ. Find out the magnetic force on the charged particle and its acceleration at this instant due to magnetic field B = 3jˆ−2kˆ,v and B are in m/s and Wb/m^2 respectively. D = 1.25 × 10^−2 m and rise of water in capillary h = 1.45 × 10^−2 m. Taking g = 9.80 m/s^2 and using the relation T = (rgh/2) × 10^3 N/m The following observations were taken for dtermining the surface tension of water by capillary tube method: diameter of capillary what is the possible error in measurement of surface tension T? October 13, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related