A charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x A charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x October 13, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related