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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A charged cork of mass m suspended by a light string is placed in uniform electric field of strength E = ( i + j ) x 10^5 N/C as shown in the figure. if in equilibrrium position tension in teh string is 2 mg /(1 +root 3 ) then angle alpha with the vertical can be

A charged cork of mass m suspended by a light string is placed in uniform electric field of strength E = ( i + j ) x 10^5 N/C as shown in the figure. if in equilibrrium position tension in teh string is 2 mg /(1 +root 3 ) then angle alpha with the vertical can be

For the situation shown in figure ( assume r >> length of dipole ) mark out the correct sentences.