A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u=931 MeV)

Assuming that about 20 MeV of energy is released per fusion reaction, 1H^2 + 1H^3 ⟶ 2He^4 . then the mass of 1H^2 consumed per day in a fusion reactor of power 1 MW will approximately be :

Find the binding energy per nucleon for 12050Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U and mass of tin nucleus mSn = 119.902199 U. (take 1U = 931 MeV)

Assuming that about 20 MeV of energy is released per fusion reaction 1H2 + 1H2 gives 2He4 + E + other particles then the mass of 1H2 consumed per day in a fusion reactor of

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