Question Answers

Sahay Sir > Question Answers > Cengage NEET by C.P Singh > Part 1 > Chapter 9 - Circular Motion > A car of mass M is moving on a horizontal circular path of radius r. At an instant its speed is v and is increasing at a rate a. 1. The net acceleration of the car is towards the centre of its path. 2. The magnitude of the frictional force on the car is greater than Mv^2/R. 3. The friction coefficient between the ground and the car in not less than βg. 4. The friction coefficient between the ground and the car is theta = tha^-1 v^2/Rg.

A car of mass M is moving on a horizontal circular path of radius r. At an instant its speed is v and is increasing at a rate a. 1. The net acceleration of the car is towards the centre of its path. 2. The magnitude of the frictional force on the car is greater than Mv^2/R. 3. The friction coefficient between the ground and the car in not less than βg. 4. The friction coefficient between the ground and the car is theta = tha^-1 v^2/Rg.

if w= i - j + k and r = i - 2j + 3k? What is the value of linear velocity