A capacitor of capacity 2 μF is charged to a potential difference of 12 V. It is then connected across an inductor of inductance 6μH. What is the current (in A) in the circuit at a time when the potential difference across the capacitor is 6.0 V? A current of 2 A is increasing at a rate of 4 A/s through a coil of inductance 1 H. Find the energy stored in the inductor per unit in the units of J/s. October 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related