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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A bulb is rated at 100 V, 100 W. It can be treated as a resistor. Find out the inductance of an inductor (called choke coil) that should be connected in series with the bulb at its rated power with the help of an ac source of 200 V and 50 Hz.

A bulb is rated at 100 V, 100 W. It can be treated as a resistor. Find out the inductance of an inductor (called choke coil) that should be connected in series with the bulb at its rated power with the help of an ac source of 200 V and 50 Hz.

A bulb is rated at 100 V a constant current 2.5 A flows. When the same inductor coil is connected to an ac source of 10 V and 50 Hz then the current is 2 A. Find out the indutance of the coil. When an inductor coil is connected to an ideal battery of emf 10 V