A body of mass m and radius r is released from rest along a smooth inclined plane of angle of inclination θ. The angular momentum of the body about the instantaneous point of contact after a time t from the instant of release is equal to A particle m starts with zero velocity along a line y=4d. The position of particle m varies as x=A sin omegat At omegat=pi//2 its angular momentum with respect to the origin August 23, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related