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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A body is project at t= 0 with a velocity 10ms−1 at an angle of 60∘ with the horizontal .The radius of curvature of its trajectory at t=1 s is R. Neglecting air resistance and taking acceleration due to gravity g=10 ms−2, the value of R is :

A body is project at t= 0 with a velocity 10ms−1 at an angle of 60∘ with the horizontal .The radius of curvature of its trajectory at t=1 s is R. Neglecting air resistance and taking acceleration due to gravity g=10 ms−2, the value of R is :

The position vector of a particle changes with time according to the relation r→(t)=15 t^2 iˆ+(4−20 t^2)jˆ What is the magnitude of the acceleration at t = 1?