A body dropped from top of a tower falls through 40 m during the last two seconds of its fall. The height of tower in m is ( g= 10 m/s^2 A body dropped from top of a tower falls through 40 m during the last two seconds of its fall. The height of tower in m is ( g= 10 m/s^2 August 23, 2020 Category: Chapter 2 - Vectors , Chapter 3 - Motion in a Straight Line , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related A car is moving along a straight road with a uniform acceleration. It passes through two points P and Q separated by a distance with velocity 30 km/h and 40 km/h respectively. The velocity of the car midway between P and Q is?A ball is dropped from the roof of a tower of height h. The total distance covered it in the last seconds of its motion is equal to the distance covered by it in first three seconds. The value of h (g=10m/s^2)From the top of a tower, 80 m high from the ground a stone is thrown in the horizontal direction with a velocity of 8ms^1. The stone reaches the ground after a time t and falls at a distance of d from the foot of the tower. Assuming g=10ms^2, the time t and distance d are given respectively by
