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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion > A block of mass m is lying on a wedge having inclination angle α=tan^−1(1/5) wedge is moving with a constant acceleration a=2ms^−2 The minimum value of coefficient of friction μ so that m remain stationary w.r.t. wedge is

A block of mass m is lying on a wedge having inclination angle α=tan^−1(1/5) wedge is moving with a constant acceleration a=2ms^−2 The minimum value of coefficient of friction μ so that m remain stationary w.r.t. wedge is

A block of mass m if coefficient of friction between the block and the surface is inclined at an angle θ to the vertical. The block will remain in equilibrium lying on a rough horizontal plane is acted upon by a horizontal force P and another force Q