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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 3 - Laws of Motion > A block of mass is placed on a surface with a vertical cross section given by y=x^3/6. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is:

A block of mass is placed on a surface with a vertical cross section given by y=x^3/6. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is:

A block of mass is placed on a surface with a vertical cross section given by y=x^3/6. If the coefficient of friction is 0.5 the maximum height above the ground at which the block can be placed without slipping is: