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Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 5 - Laws of Motion > A block of mass 2 kg is placed on the floor. The coefficient of static friction is μs=0.54. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and floor (taking g=10m/sec2)

A block of mass 2 kg is placed on the floor. The coefficient of static friction is μs=0.54. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and floor (taking g=10m/sec2)

September 11, 2020
Category: Chapter 5 - Laws of Motion , MTG NEET Physics , Part 1 ,

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A block of mass 2 kg is placed on the floor. The coefficient of static friction is μs​=0.54. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and floor (taking g=10m/sec2)

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A block of mass 2 kg is placed on the floor. The coefficient of static friction is μs=0.54. If a force of 2.8 N is applied on the block parallel to the floor, the force of friction between the block and floor (taking g=10m/sec2)