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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A bar magnetic with poles 25 cm apart and pole strength 14⋅4 Am rests with its centre on a frictionless pivot. It is held in equilibrium at 60∘ to a uniform magnetic field of induction 0⋅25 T by applying a force F at right angles to its axis, 10cm from the pivot. Calculate the value of F. What will happen if the force is removed?

A bar magnetic with poles 25 cm apart and pole strength 14⋅4 Am rests with its centre on a frictionless pivot. It is held in equilibrium at 60∘ to a uniform magnetic field of induction 0⋅25 T by applying a force F at right angles to its axis, 10cm from the pivot. Calculate the value of F. What will happen if the force is removed?

joining the two poles the magnetic field will be Zero ? Two like magnetic poles of strength 25 Am and 64 Am are situated 1 m apart in air. At what point on the line