A ball is dropped from the top of 80 m high tower. If after 2 s of fall the gravity (g = 10 m/s^2 ) disappears, then time taken to reach ground since the gravity disappeared is A ball is dropped from the top of 80 m high tower. If after 2 s of fall the gravity (g = 10 m/s^2 ) disappears then time taken to reach ground since the gravity disappeared is September 10, 2020 Category: Chapter 3 - Motion in One Dimension , MTG NEET Physics , Part 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related Particle A moves along X-axis with a uniform velocity of magnitude 10 m/s. Particle B moves with uniform velocity 20m/s along a direction making an angle of 60o with the positive direction of X-axis as shown in the figure. The relative velocity of B with respect to that of A is.A ball is dropped from the top of a 100 m high tower on a planet. In the last (1/2)s before hitting the ground, it covers a distance of 19 m. Acceleration due to gravity (in ms^–2) near the surface on that planet is _____A ball is dropped from a tower of height h under gravity. If it takes 4s to reach the ground from height h/2, then time taken by it to reach from h to h/2 is nearly:
