A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t=18 s. What is the value of v? (Take g=10m/s^2) The motion of a particle along a straight line is described by equation x = 8 + 12 t - t^3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is August 27, 2020 Category: Chapter 3 - Motion in a Straight Line , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related