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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A 200Ω resistor is connected in series with a 5 (μ)F capacitor. The voltage across the resistor is VR = ( 1.20 V)cos ( 2500 rads−1)t. (a) Derive an expression for the circuit current. (b) Determine the capactive reactance of the capacitor. (c ) derive an experssion for the voltage across the capacitor.

A 200Ω resistor is connected in series with a 5 (μ)F capacitor. The voltage across the resistor is VR = ( 1.20 V)cos ( 2500 rads−1)t. (a) Derive an expression for the circuit current. (b) Determine the capactive reactance of the capacitor. (c ) derive an experssion for the voltage across the capacitor.

and the voltage amplitude across each circuit element. C= 0.50 (μ)F In the series curcuit of fig L= 60 mH source amplitude is E0=50Vandω=10000rads−1. Find the reactances XLandXC suppose R= 300 Ω the current amplitude I0 the impedance Z the phase angle ϕ