6.In figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE. 6.In figure AB = AD and ∠BAD = ∠EAC. Show that BC = DE. AC = AE October 15, 2020 Category: Chapter 7 - Triangles , Maths , NCERT Class 9 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related Example 6 : In an isosceles triangle ABC with AB = AC, D and E are points on BC such that BE = CD (see figure). Show that AD = AE.In figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB^2 = BC × BD (ii) AC^2 = BC × DC (iii) AD^2 = BD × CDIf a line intersects sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC, prove that AD/AB = AE/AC.
