6. ABCD is such a quadrilateral that A is the centre of the circle passing through B, C and D. Prove that ∠CBD + ∠CDB = 1/2 ∠BAD 6. ABCD is such a quadrilateral that A is the centre of the circle passing through B C and D. Prove that ∠CBD + ∠CDB = 1/2 ∠BAD July 2, 2021 Category: Chapter 10 - Circles , Maths , NCERT Class 9 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related A quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB+CD=AD+BC.If A(–5, 7), B(– 4, –5), C(–1, –6) and D(4, 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD4. AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see Fig. 7.50). Show that angle A > angle C and angle B > angle D.
