5. Q is a point on the side SR of a ∆ PSR such that PQ = PR. Prove that PS > PQ. 5. Q is a point on the side SR of a ∆ PSR such that PQ = PR. Prove that PS > PQ. June 30, 2021 Category: Chapter 7 - Triangles , Maths , NCERT Class 9 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related 5. In Fig 7.51, PR > PQ and PS bisect angle QPR. Prove that angle PSR > angle PSQ.In Fig.7.3, PQ > PR and QS and RS are the bisectors of ∠Q and ∠R, respectively. Show that SQ > SR.S is any point in the interior of ∆ PQR. Show that SQ + SR < PQ + PR.
