4. In Fig. 9.16, P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD) 4. In Fig. 9.16 P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD) October 15, 2020 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related