4. In ∆ ABC, D is the mid-point of AB and P is any point on BC. If CQ || PD meets AB in Q (Fig. 9.14), then prove that ar (BPQ) = 1/2 ar (ABC). 4. In ∆ ABC D is the mid-point of AB and P is any point on BC. If CQ || PD meets AB in Q (Fig. 9.14) then prove that ar (BPQ) = 1/2 ar (ABC). July 1, 2021 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related 8. In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q (Fig. 9.18). Prove that ar (ABCD) = ar (APQD)18. P is the mid-point of the side CD of a parallelogram ABCD. A line through C parallel to PA intersects AB at Q and DA produced at R. Prove that DA = AR and CQ = QR.In Fig. 9.23, BD || CA, E is mid-point of CA and BD = 1/2 CA. Prove that ar (ABC) = 2ar (DBC)€
