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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > 20 g of a non-volatile solute is added to 500 g of solvent. Freezing point of solvent =5.48∘C and solution =4.47∘C.Kf=1.93∘/m. Molecular mas of the solute is

20 g of a non-volatile solute is added to 500 g of solvent. Freezing point of solvent =5.48∘C and solution =4.47∘C.Kf=1.93∘/m. Molecular mas of the solute is

20 g of a non-volatile solute is added to 500 g of solvent. Freezing point of solvent =5.48∘C and solution =4.47∘C.Kf=1.93∘/m. Molecular mas of the solute is