1. In a ∆ PQR, PR^2 – PQ^2 = QR^2 and M is a point on side PR such that QM ⊥ PR. Prove that QM^2 = PM × MR. 1. In a ∆ PQR PR^2 – PQ^2 = QR^2 and M is a point on side PR such that QM ⊥ PR. Prove that QM^2 = PM × MR. July 5, 2021 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
