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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > 0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 degree C . The molecular mass of the substance ( Kf = 0.5.12 degree kg C /mol )

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 degree C . The molecular mass of the substance ( Kf = 0.5.12 degree kg C /mol )

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 degree C . The molecular mass of the substance ( Kf = 0.5.12 degree kg C /mol )